Algebra

Arithmetic Series

Sum of arithmetic sequence

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k = 1 \sum n (a + (k - 1) d) = \frac{n}{2} (2 a + (n - 1) d)

\sum_{k=1}^{n} (a + (k-1)d) = \frac{n}{2}(2a + (n-1)d)

Solution to quadratic equations ax² + bx + c = 0

Expansion of (x+y)ⁿ

Factorization of difference of two squares

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